Simple Shell

In a shell script it’s easy: dollar zero is the filename of the script, one is the first argument, two is the second and so on.

#!/bin/bash echo "Usage: $0 <arg1> [arg2]"

1 2	#!/bin/bash echo "Usage: $0 <arg1> [arg2]"

So how do you perform this operation in python?

Python Plurality

As you would expect, there are several ways to do this in a python script. Using stack from the inspect module will give you the full path and filename of how it was executed. If you run from a relative path such as ./src/file then the stack item will contain just that part.

#!/usr/bin/env python import inspect print inspect.stack()[0][1]

1 2 3

#!/usr/bin/env python import inspect print inspect.stack()[0][1]

And if you’re curious, executing this from python’s interactive shell instead of a python script yields this instead:

>>> import inspect >>> inspect.stack()[0][1] '<stdin>' >>> inspect.stack()[0] (<frame object at 0x1977480>, '<stdin>', 1, '<module>', None, None)

1 2 3 4 5

>>> import inspect >>> inspect.stack()[0][1] '<stdin>' >>> inspect.stack()[0] (<frame object at 0x1977480>, '<stdin>', 1, '<module>', None, None)

I can imagine there are other ways to break this and end up with or a pipe or something weird instead, but for most cases, this should work just fine.

Posted on July 5th, by admica in howto, python.

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current filename name running script self